Atomistry » Boron » Chemical properties » Boron imide
Atomistry »
  Boron »
    Chemical properties »
      Boron imide »

Boron imide, B2(NH)3

Boron imide, B2(NH)3, is best prepared by heating the compound B2S3.6NH3 at 115° to 120° in a rapid stream of ammonia for some days: -

B2S3.6NH3 = B2(NH)3 + 3NH4.SH.

Boron imide is a light, white powder, insoluble in alcohol, ether, carbon disulphide, and liquid ammonia. It begins to decompose at 125° to 130° with the evolution of ammonia, and at a slightly higher temperature is completely resolved into, boron nitride and ammonia. When boiled with water, boron imide is decomposed into ammonia and boric acid.

Boron imide is a feebly basic compound, and when added to liquid hydrogen chloride it forms a white hydrochloride, B2(NH)3.3HCl, insoluble in organic media, and decomposed by heat or water.

Last articles

Zn in 7VD8
Zn in 7V1R
Zn in 7V1Q
Zn in 7VPF
Zn in 7T85
Zn in 7T5F
Zn in 7NF9
Zn in 7M4M
Zn in 7M4O
Zn in 7M4N
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy