The Boron Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Boron.
B -> B+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Boron is:
BN+ -> B(N+1)+ + e-
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B -> B1+ = 800.6 kJ/mol = 191.53 Kcal/mol
B1+ -> B2+ = 2427 kJ/mol = 580.62 Kcal/mol
B2+ -> B3+ = 3660 kJ/mol = 875.60 Kcal/mol
B3+ -> B4+ = 25025 kJ/mol = 5986.84 Kcal/mol
B4+ -> B5+ = 32822 kJ/mol = 7852.15 Kcal/mol
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