Atomistry » Boron » Energy
Atomistry »
  Boron »
    Energy »

Boron Ionization Energy

The Boron Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Boron.
B -> B+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Boron is:
BN+ -> B(N+1)+ + e-

Ionization Energy

B -> B1+ = 800.6 kJ/mol = 191.53 Kcal/mol
B1+ -> B2+ = 2427 kJ/mol = 580.62 Kcal/mol
B2+ -> B3+ = 3660 kJ/mol = 875.60 Kcal/mol
B3+ -> B4+ = 25025 kJ/mol = 5986.84 Kcal/mol
B4+ -> B5+ = 32822 kJ/mol = 7852.15 Kcal/mol

Last articles

Zn in 7WT5
Zn in 7WTU
Zn in 7WTV
Zn in 7WTT
Zn in 7WT4
Zn in 7WT3
Zn in 7WSS
Zn in 7WT2
Zn in 7WT0
Zn in 7WT1
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy