Atomistry » Boron » Energy
Atomistry »
  Boron »
    Energy »

Boron Ionization Energy

The Boron Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Boron.
B -> B+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Boron is:
BN+ -> B(N+1)+ + e-

Ionization Energy

B -> B1+ = 800.6 kJ/mol = 191.53 Kcal/mol
B1+ -> B2+ = 2427 kJ/mol = 580.62 Kcal/mol
B2+ -> B3+ = 3660 kJ/mol = 875.60 Kcal/mol
B3+ -> B4+ = 25025 kJ/mol = 5986.84 Kcal/mol
B4+ -> B5+ = 32822 kJ/mol = 7852.15 Kcal/mol

Last articles

Zn in 9FD2
Zn in 9GUW
Zn in 9GUX
Zn in 9F7C
Zn in 9GUR
Zn in 9F7A
Zn in 9DDE
Zn in 9DBY
Zn in 9EBZ
Zn in 9DGG
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy