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Atomistry » Boron » Chemical properties » Tetraborodecahydride | ||||||||||||||
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Tetraborodecahydride, B4H10
Tetraborodecahydride or borobutane, B4H10, is a colourless, very volatile liquid which boils at 16° to 17° C., and freezes at about -112° C. The vapour density is 27.0 (H = 1), in accordance with the formula given. The vapour pressures at various temperatures are as follows: -
The hydride has a very disagreeable odour. A few bubbles when inhaled affect respiration and cause headache. It is extremely unstable, decomposing in a few hours at ordinary temperatures into a series of other hydrides. It is decomposed by electric sparks, and ignites spontaneously in air or oxygen, burning with a green flame. Nitric acid oxidises it with explosive violence. It is slowly decomposed by water, the final result being expressed by the equation: - B4H10 + 12H2O = 4H3BO3 + 11H2. Aqueous sodium hydroxide rapidly and completely absorbs the hydride, producing a hypoborate, but hydrogen is slowly evolved, and the net result may be expressed thus: - B4H10 + 4NaOH + 4H2O = 4NaBO2 + 11H2. The hydride is decomposed by alcohol and reacts with ammonia, but its solution in benzene is very stable towards oxygen. |
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